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40443040211311 is a prime number
BaseRepresentation
bin10010011001000011000010…
…00010111010000101101111
312022012022120000020122200201
421030201201002322011233
520300104321243230221
6222003135353334331
711342625144516253
oct1114414102720557
9168168500218621
1040443040211311
1111982884940241
1246521704073a7
1319749baaab65a
149db64c91c263
154a2039e85891
hex24c8610ba16f

40443040211311 has 2 divisors, whose sum is σ = 40443040211312. Its totient is φ = 40443040211310.

The previous prime is 40443040211309. The next prime is 40443040211317. The reversal of 40443040211311 is 11311204034404.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40443040211311 - 21 = 40443040211309 is a prime.

Together with 40443040211309, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 40443040211311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40443040211317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20221520105655 + 20221520105656.

It is an arithmetic number, because the mean of its divisors is an integer number (20221520105656).

Almost surely, 240443040211311 is an apocalyptic number.

40443040211311 is a deficient number, since it is larger than the sum of its proper divisors (1).

40443040211311 is an equidigital number, since it uses as much as digits as its factorization.

40443040211311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 40443040211311 its reverse (11311204034404), we get a palindrome (51754244245715).

The spelling of 40443040211311 in words is "forty trillion, four hundred forty-three billion, forty million, two hundred eleven thousand, three hundred eleven".