Base | Representation |
---|---|
bin | 10010011001000011000010… |
… | …00010111010000101101111 |
3 | 12022012022120000020122200201 |
4 | 21030201201002322011233 |
5 | 20300104321243230221 |
6 | 222003135353334331 |
7 | 11342625144516253 |
oct | 1114414102720557 |
9 | 168168500218621 |
10 | 40443040211311 |
11 | 11982884940241 |
12 | 46521704073a7 |
13 | 19749baaab65a |
14 | 9db64c91c263 |
15 | 4a2039e85891 |
hex | 24c8610ba16f |
40443040211311 has 2 divisors, whose sum is σ = 40443040211312. Its totient is φ = 40443040211310.
The previous prime is 40443040211309. The next prime is 40443040211317. The reversal of 40443040211311 is 11311204034404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40443040211311 - 21 = 40443040211309 is a prime.
Together with 40443040211309, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 40443040211311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40443040211317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20221520105655 + 20221520105656.
It is an arithmetic number, because the mean of its divisors is an integer number (20221520105656).
Almost surely, 240443040211311 is an apocalyptic number.
40443040211311 is a deficient number, since it is larger than the sum of its proper divisors (1).
40443040211311 is an equidigital number, since it uses as much as digits as its factorization.
40443040211311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 40443040211311 its reverse (11311204034404), we get a palindrome (51754244245715).
The spelling of 40443040211311 in words is "forty trillion, four hundred forty-three billion, forty million, two hundred eleven thousand, three hundred eleven".
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