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40452320115 = 3257911378993
BaseRepresentation
bin100101101011001001…
…010110101101110011
310212102012011210001100
4211223021112231303
51130321243220430
630330013335443
72631306022224
oct455311265563
9125365153040
1040452320115
1116179309919
127a0b497583
133a789b22bc
141d5a6b124b
1510bb582960
hex96b256b73

40452320115 has 24 divisors (see below), whose sum is σ = 71004922560. Its totient is φ = 21301473024.

The previous prime is 40452320099. The next prime is 40452320137. The reversal of 40452320115 is 51102325404.

40452320115 is a `hidden beast` number, since 4 + 0 + 4 + 523 + 20 + 115 = 666.

It is not a de Polignac number, because 40452320115 - 24 = 40452320099 is a prime.

It is a super-2 number, since 2×404523201152 (a number of 22 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5685942 + ... + 5693051.

It is an arithmetic number, because the mean of its divisors is an integer number (2958538440).

Almost surely, 240452320115 is an apocalyptic number.

40452320115 is a gapful number since it is divisible by the number (45) formed by its first and last digit.

40452320115 is a deficient number, since it is larger than the sum of its proper divisors (30552602445).

40452320115 is a wasteful number, since it uses less digits than its factorization.

40452320115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11379083 (or 11379080 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 27.

Adding to 40452320115 its reverse (51102325404), we get a palindrome (91554645519).

The spelling of 40452320115 in words is "forty billion, four hundred fifty-two million, three hundred twenty thousand, one hundred fifteen".

Divisors: 1 3 5 9 15 45 79 237 395 711 1185 3555 11378993 34136979 56894965 102410937 170684895 512054685 898940447 2696821341 4494702235 8090464023 13484106705 40452320115