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40455213303 = 313485071101
BaseRepresentation
bin100101101011010100…
…011001000011110111
310212102101121202202110
4211223110121003313
51130323013311203
630330155342103
72631342432201
oct455324310367
9125371552673
1040455213303
111617aa0558a
127a10451933
133a7948614b
141d5ac25771
1510bb954d03
hex96b5190f7

40455213303 has 4 divisors (see below), whose sum is σ = 53940284408. Its totient is φ = 26970142200.

The previous prime is 40455213301. The next prime is 40455213343. The reversal of 40455213303 is 30331255404.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 40455213303 - 21 = 40455213301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40455213301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6742535548 + ... + 6742535553.

It is an arithmetic number, because the mean of its divisors is an integer number (13485071102).

Almost surely, 240455213303 is an apocalyptic number.

40455213303 is a deficient number, since it is larger than the sum of its proper divisors (13485071105).

40455213303 is a wasteful number, since it uses less digits than its factorization.

40455213303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13485071104.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 40455213303 its reverse (30331255404), we get a palindrome (70786468707).

The spelling of 40455213303 in words is "forty billion, four hundred fifty-five million, two hundred thirteen thousand, three hundred three".

Divisors: 1 3 13485071101 40455213303