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40468925353 is a prime number
BaseRepresentation
bin100101101100001000…
…101100101110101001
310212110100102102011011
4211230020230232221
51130340021102403
630331405303521
72631600122053
oct455410545651
9125410372134
1040468925353
111618772065a
127a14b64ba1
133a7c27749c
141d5c9948d3
1510bcc62a6d
hex96c22cba9

40468925353 has 2 divisors, whose sum is σ = 40468925354. Its totient is φ = 40468925352.

The previous prime is 40468925347. The next prime is 40468925359. The reversal of 40468925353 is 35352986404.

It is a balanced prime because it is at equal distance from previous prime (40468925347) and next prime (40468925359).

It can be written as a sum of positive squares in only one way, i.e., 39966806889 + 502118464 = 199917^2 + 22408^2 .

It is a cyclic number.

It is not a de Polignac number, because 40468925353 - 213 = 40468917161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40468925297 and 40468925306.

It is not a weakly prime, because it can be changed into another prime (40468925359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20234462676 + 20234462677.

It is an arithmetic number, because the mean of its divisors is an integer number (20234462677).

Almost surely, 240468925353 is an apocalyptic number.

It is an amenable number.

40468925353 is a deficient number, since it is larger than the sum of its proper divisors (1).

40468925353 is an equidigital number, since it uses as much as digits as its factorization.

40468925353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3110400, while the sum is 49.

The spelling of 40468925353 in words is "forty billion, four hundred sixty-eight million, nine hundred twenty-five thousand, three hundred fifty-three".