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40505411207 is a prime number
BaseRepresentation
bin100101101110010011…
…111000011010000111
310212112220002002100002
4211232103320122013
51130423341124312
630335151311515
72632522212602
oct455623703207
9125486062302
1040505411207
11161a6280a58
127a2521b59b
133a869b0651
141d63771339
1510c106d4c2
hex96e4f8687

40505411207 has 2 divisors, whose sum is σ = 40505411208. Its totient is φ = 40505411206.

The previous prime is 40505411203. The next prime is 40505411209. The reversal of 40505411207 is 70211450504.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40505411207 - 22 = 40505411203 is a prime.

It is a super-2 number, since 2×405054112072 (a number of 22 digits) contains 22 as substring.

Together with 40505411209, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40505411207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40505411203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20252705603 + 20252705604.

It is an arithmetic number, because the mean of its divisors is an integer number (20252705604).

Almost surely, 240505411207 is an apocalyptic number.

40505411207 is a deficient number, since it is larger than the sum of its proper divisors (1).

40505411207 is an equidigital number, since it uses as much as digits as its factorization.

40505411207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5600, while the sum is 29.

The spelling of 40505411207 in words is "forty billion, five hundred five million, four hundred eleven thousand, two hundred seven".