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4051350132437 is a prime number
BaseRepresentation
bin111010111101000111010…
…010010001011011010101
3112100022020120000201002002
4322331013102101123111
51012334131113214222
612341055313325045
7565462142635046
oct72750722213325
915308216021062
104051350132437
111322193593153
12555218b66785
1323506b4a6b9a
1410012d0c08cd
15705b9144392
hex3af474916d5

4051350132437 has 2 divisors, whose sum is σ = 4051350132438. Its totient is φ = 4051350132436.

The previous prime is 4051350132371. The next prime is 4051350132469. The reversal of 4051350132437 is 7342310531504.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2716461052561 + 1334889079876 = 1648169^2 + 1155374^2 .

It is a cyclic number.

It is not a de Polignac number, because 4051350132437 - 240 = 2951838504661 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4051350132437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4051350132937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2025675066218 + 2025675066219.

It is an arithmetic number, because the mean of its divisors is an integer number (2025675066219).

Almost surely, 24051350132437 is an apocalyptic number.

It is an amenable number.

4051350132437 is a deficient number, since it is larger than the sum of its proper divisors (1).

4051350132437 is an equidigital number, since it uses as much as digits as its factorization.

4051350132437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 38.

The spelling of 4051350132437 in words is "four trillion, fifty-one billion, three hundred fifty million, one hundred thirty-two thousand, four hundred thirty-seven".