Base | Representation |
---|---|
bin | 111010111110101100000… |
… | …101010000111000001111 |
3 | 112100110121102002220122211 |
4 | 322332230011100320033 |
5 | 1012401112023034020 |
6 | 12341535203251251 |
7 | 565552065643564 |
oct | 72765405207017 |
9 | 15313542086584 |
10 | 4053041221135 |
11 | 132298111a115 |
12 | 55560b379b27 |
13 | 23527a95329a |
14 | 10024d92686b |
15 | 7066783785a |
hex | 3afac150e0f |
4053041221135 has 8 divisors (see below), whose sum is σ = 4863660765840. Its totient is φ = 3242425443264.
The previous prime is 4053041221123. The next prime is 4053041221183. The reversal of 4053041221135 is 5311221403504.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4053041221135 - 221 = 4053039123983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4053041221097 and 4053041221106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2719419 + ... + 3937171.
It is an arithmetic number, because the mean of its divisors is an integer number (607957595730).
Almost surely, 24053041221135 is an apocalyptic number.
4053041221135 is a deficient number, since it is larger than the sum of its proper divisors (810619544705).
4053041221135 is a wasteful number, since it uses less digits than its factorization.
4053041221135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1883417.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 4053041221135 its reverse (5311221403504), we get a palindrome (9364262624639).
The spelling of 4053041221135 in words is "four trillion, fifty-three billion, forty-one million, two hundred twenty-one thousand, one hundred thirty-five".
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