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4053041221135 = 56656591217753
BaseRepresentation
bin111010111110101100000…
…101010000111000001111
3112100110121102002220122211
4322332230011100320033
51012401112023034020
612341535203251251
7565552065643564
oct72765405207017
915313542086584
104053041221135
11132298111a115
1255560b379b27
1323527a95329a
1410024d92686b
157066783785a
hex3afac150e0f

4053041221135 has 8 divisors (see below), whose sum is σ = 4863660765840. Its totient is φ = 3242425443264.

The previous prime is 4053041221123. The next prime is 4053041221183. The reversal of 4053041221135 is 5311221403504.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4053041221135 - 221 = 4053039123983 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4053041221097 and 4053041221106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2719419 + ... + 3937171.

It is an arithmetic number, because the mean of its divisors is an integer number (607957595730).

Almost surely, 24053041221135 is an apocalyptic number.

4053041221135 is a deficient number, since it is larger than the sum of its proper divisors (810619544705).

4053041221135 is a wasteful number, since it uses less digits than its factorization.

4053041221135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1883417.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 4053041221135 its reverse (5311221403504), we get a palindrome (9364262624639).

The spelling of 4053041221135 in words is "four trillion, fifty-three billion, forty-one million, two hundred twenty-one thousand, one hundred thirty-five".

Divisors: 1 5 665659 1217753 3328295 6088765 810608244227 4053041221135