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40531026031 is a prime number
BaseRepresentation
bin100101101111110101…
…100110000001101111
310212121200021110021021
4211233311212001233
51131001420313111
630341504315011
72633253015436
oct455765460157
9125550243237
1040531026031
1116209786831
127a31912a67
133a8c0ab652
141d66d1c11d
1510c342cd71
hex96fd6606f

40531026031 has 2 divisors, whose sum is σ = 40531026032. Its totient is φ = 40531026030.

The previous prime is 40531025993. The next prime is 40531026061. The reversal of 40531026031 is 13062013504.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40531026031 - 211 = 40531023983 is a prime.

It is a super-2 number, since 2×405310260312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40531025987 and 40531026005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40531026061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20265513015 + 20265513016.

It is an arithmetic number, because the mean of its divisors is an integer number (20265513016).

Almost surely, 240531026031 is an apocalyptic number.

40531026031 is a deficient number, since it is larger than the sum of its proper divisors (1).

40531026031 is an equidigital number, since it uses as much as digits as its factorization.

40531026031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 40531026031 its reverse (13062013504), we get a palindrome (53593039535).

The spelling of 40531026031 in words is "forty billion, five hundred thirty-one million, twenty-six thousand, thirty-one".