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40531102013 is a prime number
BaseRepresentation
bin100101101111110101…
…111000100100111101
310212121200102022111102
4211233311320210331
51131001430231023
630341510102445
72633253453113
oct455765704475
9125550368442
1040531102013
1116209828926
127a3194aa25
133a8c1070cc
141d66d3bab3
1510c3445628
hex96fd7893d

40531102013 has 2 divisors, whose sum is σ = 40531102014. Its totient is φ = 40531102012.

The previous prime is 40531101943. The next prime is 40531102033. The reversal of 40531102013 is 31020113504.

It is an a-pointer prime, because the next prime (40531102033) can be obtained adding 40531102013 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33748261849 + 6782840164 = 183707^2 + 82358^2 .

It is a cyclic number.

It is not a de Polignac number, because 40531102013 - 210 = 40531100989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40531102033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20265551006 + 20265551007.

It is an arithmetic number, because the mean of its divisors is an integer number (20265551007).

Almost surely, 240531102013 is an apocalyptic number.

It is an amenable number.

40531102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

40531102013 is an equidigital number, since it uses as much as digits as its factorization.

40531102013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 20.

Adding to 40531102013 its reverse (31020113504), we get a palindrome (71551215517).

The spelling of 40531102013 in words is "forty billion, five hundred thirty-one million, one hundred two thousand, thirteen".