Base | Representation |
---|---|
bin | 101110000101000010101110… |
… | …0110010001111010100100111 |
3 | 1222011002120112112110020212121 |
4 | 1130022011130302033110213 |
5 | 411111123142302230210 |
6 | 3554010212102530411 |
7 | 151241631021620350 |
oct | 13412053462172447 |
9 | 1864076475406777 |
10 | 405313325430055 |
11 | 108166463788269 |
12 | 39560530736a07 |
13 | 14520b62075273 |
14 | 72133abbb0d27 |
15 | 31cd1e2ce46da |
hex | 170a15cc8f527 |
405313325430055 has 32 divisors (see below), whose sum is σ = 598204276583040. Its totient is φ = 257292161925120.
The previous prime is 405313325430017. The next prime is 405313325430077. The reversal of 405313325430055 is 550034523313504.
It is not a de Polignac number, because 405313325430055 - 213 = 405313325421863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 405313325429993 and 405313325430020.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5583560970 + ... + 5583633559.
It is an arithmetic number, because the mean of its divisors is an integer number (18693883643220).
Almost surely, 2405313325430055 is an apocalyptic number.
405313325430055 is a deficient number, since it is larger than the sum of its proper divisors (192890951152985).
405313325430055 is a wasteful number, since it uses less digits than its factorization.
405313325430055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11167194619.
The product of its (nonzero) digits is 1620000, while the sum is 43.
Adding to 405313325430055 its reverse (550034523313504), we get a palindrome (955347848743559).
The spelling of 405313325430055 in words is "four hundred five trillion, three hundred thirteen billion, three hundred twenty-five million, four hundred thirty thousand, fifty-five".
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