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40531443313 is a prime number
BaseRepresentation
bin100101101111110111…
…001011111001110001
310212121201001122200011
4211233313023321301
51131002022141223
630341521254521
72633256404134
oct455767137161
9125551048604
1040531443313
1116209a41299
127a31a94441
133a8c1c656a
141d66dca21b
1510c34b180d
hex96fdcbe71

40531443313 has 2 divisors, whose sum is σ = 40531443314. Its totient is φ = 40531443312.

The previous prime is 40531443311. The next prime is 40531443343. The reversal of 40531443313 is 31334413504.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28355865664 + 12175577649 = 168392^2 + 110343^2 .

It is a cyclic number.

It is not a de Polignac number, because 40531443313 - 21 = 40531443311 is a prime.

Together with 40531443311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (40531443311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20265721656 + 20265721657.

It is an arithmetic number, because the mean of its divisors is an integer number (20265721657).

Almost surely, 240531443313 is an apocalyptic number.

It is an amenable number.

40531443313 is a deficient number, since it is larger than the sum of its proper divisors (1).

40531443313 is an equidigital number, since it uses as much as digits as its factorization.

40531443313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 40531443313 its reverse (31334413504), we get a palindrome (71865856817).

The spelling of 40531443313 in words is "forty billion, five hundred thirty-one million, four hundred forty-three thousand, three hundred thirteen".