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405404999999 is a prime number
BaseRepresentation
bin1011110011001000000…
…01010110000100111111
31102202102101000211002222
411321210001112010333
523120232134444444
6510123540035555
741201212433336
oct5714401260477
91382371024088
10405404999999
11146a2760a94a
12666a1392bbb
132c2ca36c2ac
141589bd6ad1d
15a82b19eeee
hex5e6405613f

405404999999 has 2 divisors, whose sum is σ = 405405000000. Its totient is φ = 405404999998.

The previous prime is 405404999977. The next prime is 405405000001. The reversal of 405404999999 is 999999404504.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 405404999999 - 216 = 405404934463 is a prime.

Together with 405405000001, it forms a pair of twin primes.

It is a Chen prime.

405404999999 is a modest number, since divided by 999999 gives 405404 as remainder.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (405404999099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202702499999 + 202702500000.

It is an arithmetic number, because the mean of its divisors is an integer number (202702500000).

Almost surely, 2405404999999 is an apocalyptic number.

405404999999 is a deficient number, since it is larger than the sum of its proper divisors (1).

405404999999 is an equidigital number, since it uses as much as digits as its factorization.

405404999999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170061120, while the sum is 71.

The spelling of 405404999999 in words is "four hundred five billion, four hundred four million, nine hundred ninety-nine thousand, nine hundred ninety-nine".