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40545012103 = 88345917341
BaseRepresentation
bin100101110000101010…
…111100100110000111
310212122122121000112221
4211300222330212013
51131014010341403
630343124153211
72633512626241
oct456052744607
9125578530487
1040545012103
1116216669772
127a36538807
133a91c6762b
141d68b1d091
1510c4791dbd
hex970abc987

40545012103 has 4 divisors (see below), whose sum is σ = 40590930328. Its totient is φ = 40499093880.

The previous prime is 40545012097. The next prime is 40545012181. The reversal of 40545012103 is 30121054504.

It is a happy number.

40545012103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40545012103 - 25 = 40545012071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40545012203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22957788 + ... + 22959553.

It is an arithmetic number, because the mean of its divisors is an integer number (10147732582).

Almost surely, 240545012103 is an apocalyptic number.

40545012103 is a deficient number, since it is larger than the sum of its proper divisors (45918225).

40545012103 is an equidigital number, since it uses as much as digits as its factorization.

40545012103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45918224.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 40545012103 its reverse (30121054504), we get a palindrome (70666066607).

The spelling of 40545012103 in words is "forty billion, five hundred forty-five million, twelve thousand, one hundred three".

Divisors: 1 883 45917341 40545012103