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40552444213 is a prime number
BaseRepresentation
bin100101110001000111…
…010011000100110101
310212200011120121111021
4211301013103010311
51131022411203323
630343551341141
72633633042221
oct456107230465
9125604517437
1040552444213
111621a885606
127a38b217b1
133a9366a428
141d69ad5781
1510c525e05d
hex9711d3135

40552444213 has 2 divisors, whose sum is σ = 40552444214. Its totient is φ = 40552444212.

The previous prime is 40552444157. The next prime is 40552444267. The reversal of 40552444213 is 31244425504.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33776191089 + 6776253124 = 183783^2 + 82318^2 .

It is a cyclic number.

It is not a de Polignac number, because 40552444213 - 217 = 40552313141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40552444013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20276222106 + 20276222107.

It is an arithmetic number, because the mean of its divisors is an integer number (20276222107).

Almost surely, 240552444213 is an apocalyptic number.

It is an amenable number.

40552444213 is a deficient number, since it is larger than the sum of its proper divisors (1).

40552444213 is an equidigital number, since it uses as much as digits as its factorization.

40552444213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76800, while the sum is 34.

Adding to 40552444213 its reverse (31244425504), we get a palindrome (71796869717).

The spelling of 40552444213 in words is "forty billion, five hundred fifty-two million, four hundred forty-four thousand, two hundred thirteen".