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4055511334121 = 13311962410317
BaseRepresentation
bin111011000000111111010…
…011111111110011101001
3112100200222120001122122222
4323000333103333303221
51012421141400142441
612343024242323425
7566000231364302
oct73007723776351
915320876048588
104055511334121
111323a2946a605
12555b9a659575
13235582619cc0
141004059d77a9
157075e60cd4b
hex3b03f4ffce9

4055511334121 has 4 divisors (see below), whose sum is σ = 4367473744452. Its totient is φ = 3743548923792.

The previous prime is 4055511334051. The next prime is 4055511334123. The reversal of 4055511334121 is 1214331155504.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 358393795600 + 3697117538521 = 598660^2 + 1922789^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4055511334121 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4055511334123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155981205146 + ... + 155981205171.

It is an arithmetic number, because the mean of its divisors is an integer number (1091868436113).

Almost surely, 24055511334121 is an apocalyptic number.

It is an amenable number.

4055511334121 is a deficient number, since it is larger than the sum of its proper divisors (311962410331).

4055511334121 is a wasteful number, since it uses less digits than its factorization.

4055511334121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 311962410330.

The product of its (nonzero) digits is 36000, while the sum is 35.

Adding to 4055511334121 its reverse (1214331155504), we get a palindrome (5269842489625).

The spelling of 4055511334121 in words is "four trillion, fifty-five billion, five hundred eleven million, three hundred thirty-four thousand, one hundred twenty-one".

Divisors: 1 13 311962410317 4055511334121