Base | Representation |
---|---|
bin | 111011000110011110011… |
… | …000001001001101100011 |
3 | 112101021012000221001200212 |
4 | 323012132120021031203 |
5 | 1013020222203132120 |
6 | 12345440523204335 |
7 | 566266210542101 |
oct | 73063630111543 |
9 | 15337160831625 |
10 | 4061401224035 |
11 | 1326481124021 |
12 | 5571630766ab |
13 | 235cb094256c |
14 | 100803d42c71 |
15 | 709a67456c5 |
hex | 3b19e609363 |
4061401224035 has 64 divisors (see below), whose sum is σ = 5306053319424. Its totient is φ = 2972945203200.
The previous prime is 4061401224029. The next prime is 4061401224061. The reversal of 4061401224035 is 5304221041604.
4061401224035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4061401224035 - 28 = 4061401223779 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4061401223992 and 4061401224010.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 288916727 + ... + 288930783.
It is an arithmetic number, because the mean of its divisors is an integer number (82907083116).
Almost surely, 24061401224035 is an apocalyptic number.
4061401224035 is a deficient number, since it is larger than the sum of its proper divisors (1244652095389).
4061401224035 is a wasteful number, since it uses less digits than its factorization.
4061401224035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14784.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 4061401224035 its reverse (5304221041604), we get a palindrome (9365622265639).
The spelling of 4061401224035 in words is "four trillion, sixty-one billion, four hundred one million, two hundred twenty-four thousand, thirty-five".
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