Base | Representation |
---|---|
bin | 1011110101101100000… |
… | …11001101111000001101 |
3 | 1102212222021122011100111 |
4 | 11322312003031320031 |
5 | 23131041443104123 |
6 | 510512301200021 |
7 | 41250263224516 |
oct | 5726603157015 |
9 | 1385867564314 |
10 | 406781222413 |
11 | 147573439145 |
12 | 66a06260011 |
13 | 2c489514097 |
14 | 1598ca4da0d |
15 | a8abde990d |
hex | 5eb60cde0d |
406781222413 has 2 divisors, whose sum is σ = 406781222414. Its totient is φ = 406781222412.
The previous prime is 406781222347. The next prime is 406781222479. The reversal of 406781222413 is 314222187604.
It is a balanced prime because it is at equal distance from previous prime (406781222347) and next prime (406781222479).
It can be written as a sum of positive squares in only one way, i.e., 406765879524 + 15342889 = 637782^2 + 3917^2 .
It is a cyclic number.
It is not a de Polignac number, because 406781222413 - 229 = 406244351501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (406781222483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 203390611206 + 203390611207.
It is an arithmetic number, because the mean of its divisors is an integer number (203390611207).
Almost surely, 2406781222413 is an apocalyptic number.
It is an amenable number.
406781222413 is a deficient number, since it is larger than the sum of its proper divisors (1).
406781222413 is an equidigital number, since it uses as much as digits as its factorization.
406781222413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129024, while the sum is 40.
The spelling of 406781222413 in words is "four hundred six billion, seven hundred eighty-one million, two hundred twenty-two thousand, four hundred thirteen".
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