Base | Representation |
---|---|
bin | 111011010010100110011… |
… | …100101111110000110101 |
3 | 112102111210102222011022210 |
4 | 323102212130233300311 |
5 | 1013223403404101013 |
6 | 12355432522044033 |
7 | 600236651514354 |
oct | 73224634576065 |
9 | 15374712864283 |
10 | 4074421550133 |
11 | 1330a52821800 |
12 | 559797649619 |
13 | 2372a72acc2c |
14 | 1012bb27d99b |
15 | 70eb985ecc3 |
hex | 3b4a672fc35 |
4074421550133 has 24 divisors (see below), whose sum is σ = 5973532625088. Its totient is φ = 2468434936000.
The previous prime is 4074421550131. The next prime is 4074421550153. The reversal of 4074421550133 is 3310551244704.
It is not a de Polignac number, because 4074421550133 - 21 = 4074421550131 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 4074421550091 and 4074421550100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4074421550131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1086048 + ... + 3054233.
It is an arithmetic number, because the mean of its divisors is an integer number (248897192712).
Almost surely, 24074421550133 is an apocalyptic number.
It is an amenable number.
4074421550133 is a deficient number, since it is larger than the sum of its proper divisors (1899111074955).
4074421550133 is a wasteful number, since it uses less digits than its factorization.
4074421550133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4143017 (or 4143006 counting only the distinct ones).
The product of its (nonzero) digits is 201600, while the sum is 39.
Adding to 4074421550133 its reverse (3310551244704), we get a palindrome (7384972794837).
The spelling of 4074421550133 in words is "four trillion, seventy-four billion, four hundred twenty-one million, five hundred fifty thousand, one hundred thirty-three".
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