Base | Representation |
---|---|
bin | 111011011100110000000… |
… | …010010100010011000101 |
3 | 112110112220221222020111001 |
4 | 323130300002110103011 |
5 | 1013413213332443133 |
6 | 12404434153413301 |
7 | 601104014306416 |
oct | 73346002242305 |
9 | 15415827866431 |
10 | 4085319812293 |
11 | 1335635591435 |
12 | 55b91940a231 |
13 | 238323105a75 |
14 | 101a3282980d |
15 | 7140650487d |
hex | 3b7300944c5 |
4085319812293 has 2 divisors, whose sum is σ = 4085319812294. Its totient is φ = 4085319812292.
The previous prime is 4085319812291. The next prime is 4085319812317. The reversal of 4085319812293 is 3922189135804.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2780682981444 + 1304636830849 = 1667538^2 + 1142207^2 .
It is a cyclic number.
It is not a de Polignac number, because 4085319812293 - 21 = 4085319812291 is a prime.
Together with 4085319812291, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4085319812291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2042659906146 + 2042659906147.
It is an arithmetic number, because the mean of its divisors is an integer number (2042659906147).
Almost surely, 24085319812293 is an apocalyptic number.
It is an amenable number.
4085319812293 is a deficient number, since it is larger than the sum of its proper divisors (1).
4085319812293 is an equidigital number, since it uses as much as digits as its factorization.
4085319812293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 55.
The spelling of 4085319812293 in words is "four trillion, eighty-five billion, three hundred nineteen million, eight hundred twelve thousand, two hundred ninety-three".
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