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41000000135 = 560713509061
BaseRepresentation
bin100110001011110010…
…100101101010000111
310220211100201210210112
4212023302211222013
51132432000001020
630500220143235
72651006152043
oct461362455207
9126740653715
1041000000135
111642a481a36
127b42997b1b
133b352bc813
141dad319023
1510ee6b82c5
hex98bca5a87

41000000135 has 8 divisors (see below), whose sum is σ = 49281058176. Its totient is φ = 32745961440.

The previous prime is 41000000051. The next prime is 41000000137. The reversal of 41000000135 is 53100000014.

41000000135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 41000000135 - 218 = 40999737991 is a prime.

It is a super-2 number, since 2×410000001352 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41000000137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6751496 + ... + 6757565.

It is an arithmetic number, because the mean of its divisors is an integer number (6160132272).

Almost surely, 241000000135 is an apocalyptic number.

41000000135 is a deficient number, since it is larger than the sum of its proper divisors (8281058041).

41000000135 is a wasteful number, since it uses less digits than its factorization.

41000000135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13509673.

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 41000000135 its reverse (53100000014), we get a palindrome (94100000149).

The spelling of 41000000135 in words is "forty-one billion, one hundred thirty-five", and thus it is an aban number.

Divisors: 1 5 607 3035 13509061 67545305 8200000027 41000000135