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41001042113 = 48779840547
BaseRepresentation
bin100110001011110110…
…100100000011000001
310220211102200202010022
4212023312210003001
51132432231321423
630500254343225
72651021051633
oct461366440301
9126742622108
1041001042113
1116430023879
127b431bab15
133b35595b85
141dad50aa53
1510ee821dc8
hex98bda40c1

41001042113 has 4 divisors (see below), whose sum is σ = 41001931440. Its totient is φ = 41000152788.

The previous prime is 41001042031. The next prime is 41001042127. The reversal of 41001042113 is 31124010014.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41001042113 - 214 = 41001025729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41001042091 and 41001042100.

It is not an unprimeable number, because it can be changed into a prime (41001042143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371495 + ... + 469052.

It is an arithmetic number, because the mean of its divisors is an integer number (10250482860).

Almost surely, 241001042113 is an apocalyptic number.

It is an amenable number.

41001042113 is a deficient number, since it is larger than the sum of its proper divisors (889327).

41001042113 is an equidigital number, since it uses as much as digits as its factorization.

41001042113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 889326.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 41001042113 its reverse (31124010014), we get a palindrome (72125052127).

The spelling of 41001042113 in words is "forty-one billion, one million, forty-two thousand, one hundred thirteen".

Divisors: 1 48779 840547 41001042113