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4100999942267 is a prime number
BaseRepresentation
bin111011101011010110101…
…001010001000001111011
3112112001101201220101002122
4323223112221101001323
51014142321441123032
612415550125151455
7602200413232154
oct73532651210173
915461351811078
104100999942267
111341251611138
125629746bb58b
13239951824c97
141026bd0d492b
1571a22db4012
hex3bad6a5107b

4100999942267 has 2 divisors, whose sum is σ = 4100999942268. Its totient is φ = 4100999942266.

The previous prime is 4100999942261. The next prime is 4100999942269. The reversal of 4100999942267 is 7622499990014.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4100999942267 - 236 = 4032280465531 is a prime.

It is a super-3 number, since 3×41009999422673 (a number of 39 digits) contains 333 as substring.

Together with 4100999942269, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4100999942261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050499971133 + 2050499971134.

It is an arithmetic number, because the mean of its divisors is an integer number (2050499971134).

Almost surely, 24100999942267 is an apocalyptic number.

4100999942267 is a deficient number, since it is larger than the sum of its proper divisors (1).

4100999942267 is an equidigital number, since it uses as much as digits as its factorization.

4100999942267 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17635968, while the sum is 62.

The spelling of 4100999942267 in words is "four trillion, one hundred billion, nine hundred ninety-nine million, nine hundred forty-two thousand, two hundred sixty-seven".