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41015441412191 is a prime number
BaseRepresentation
bin10010101001101101001101…
…10100001101000001011111
312101020001000122002110011202
421110312212310031001133
520333444111000142231
6223122122245510115
711432160605453141
oct1124664664150137
9171201018073152
1041015441412191
1112083607452544
12472509841233b
1319b697c99019c
14a1b22d60ac91
154b1d8bddb5cb
hex254da6d0d05f

41015441412191 has 2 divisors, whose sum is σ = 41015441412192. Its totient is φ = 41015441412190.

The previous prime is 41015441412167. The next prime is 41015441412241. The reversal of 41015441412191 is 19121414451014.

41015441412191 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41015441412191 is a prime.

It is a super-3 number, since 3×410154414121913 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41015441472191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20507720706095 + 20507720706096.

It is an arithmetic number, because the mean of its divisors is an integer number (20507720706096).

Almost surely, 241015441412191 is an apocalyptic number.

41015441412191 is a deficient number, since it is larger than the sum of its proper divisors (1).

41015441412191 is an equidigital number, since it uses as much as digits as its factorization.

41015441412191 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 38.

The spelling of 41015441412191 in words is "forty-one trillion, fifteen billion, four hundred forty-one million, four hundred twelve thousand, one hundred ninety-one".