Base | Representation |
---|---|
bin | 111011101100011010100… |
… | …110010010100111001011 |
3 | 112112011100012010222010201 |
4 | 323230122212102213023 |
5 | 1014202140320404003 |
6 | 12420255212553031 |
7 | 602240565536434 |
oct | 73543246224713 |
9 | 15464305128121 |
10 | 4102140013003 |
11 | 134178710515a |
12 | 563032482777 |
13 | 239aa3a95756 |
14 | 10278a6a448b |
15 | 71a8d012b1d |
hex | 3bb1a9929cb |
4102140013003 has 4 divisors (see below), whose sum is σ = 4102210546240. Its totient is φ = 4102069479768.
The previous prime is 4102140012991. The next prime is 4102140013061. The reversal of 4102140013003 is 3003100412014.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4102140013003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4102140613003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35179308 + ... + 35295721.
It is an arithmetic number, because the mean of its divisors is an integer number (1025552636560).
Almost surely, 24102140013003 is an apocalyptic number.
4102140013003 is a deficient number, since it is larger than the sum of its proper divisors (70533237).
4102140013003 is an equidigital number, since it uses as much as digits as its factorization.
4102140013003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70533236.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 4102140013003 its reverse (3003100412014), we get a palindrome (7105240425017).
The spelling of 4102140013003 in words is "four trillion, one hundred two billion, one hundred forty million, thirteen thousand, three".
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