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4102140013003 = 5820770475029
BaseRepresentation
bin111011101100011010100…
…110010010100111001011
3112112011100012010222010201
4323230122212102213023
51014202140320404003
612420255212553031
7602240565536434
oct73543246224713
915464305128121
104102140013003
11134178710515a
12563032482777
13239aa3a95756
1410278a6a448b
1571a8d012b1d
hex3bb1a9929cb

4102140013003 has 4 divisors (see below), whose sum is σ = 4102210546240. Its totient is φ = 4102069479768.

The previous prime is 4102140012991. The next prime is 4102140013061. The reversal of 4102140013003 is 3003100412014.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4102140013003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4102140613003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35179308 + ... + 35295721.

It is an arithmetic number, because the mean of its divisors is an integer number (1025552636560).

Almost surely, 24102140013003 is an apocalyptic number.

4102140013003 is a deficient number, since it is larger than the sum of its proper divisors (70533237).

4102140013003 is an equidigital number, since it uses as much as digits as its factorization.

4102140013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70533236.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 4102140013003 its reverse (3003100412014), we get a palindrome (7105240425017).

The spelling of 4102140013003 in words is "four trillion, one hundred two billion, one hundred forty million, thirteen thousand, three".

Divisors: 1 58207 70475029 4102140013003