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4102144000127 is a prime number
BaseRepresentation
bin111011101100011010110…
…101100000000001111111
3112112011100110122112102222
4323230122311200001333
51014202142331001002
612420255434235555
7602240644453625
oct73543265400177
915464313575388
104102144000127
1113417893887a8
12563033885bbb
13239aa48604b4
1410278b021515
1571a8d54e1a2
hex3bb1ad6007f

4102144000127 has 2 divisors, whose sum is σ = 4102144000128. Its totient is φ = 4102144000126.

The previous prime is 4102144000043. The next prime is 4102144000217. The reversal of 4102144000127 is 7210004412014.

Together with next prime (4102144000217) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4102144000127 - 28 = 4102143999871 is a prime.

It is a super-2 number, since 2×41021440001272 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4102144000096 and 4102144000105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4102144000027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2051072000063 + 2051072000064.

It is an arithmetic number, because the mean of its divisors is an integer number (2051072000064).

Almost surely, 24102144000127 is an apocalyptic number.

4102144000127 is a deficient number, since it is larger than the sum of its proper divisors (1).

4102144000127 is an equidigital number, since it uses as much as digits as its factorization.

4102144000127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1792, while the sum is 26.

The spelling of 4102144000127 in words is "four trillion, one hundred two billion, one hundred forty-four million, one hundred twenty-seven", and thus it is an aban number.