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41032003101 = 313677334367
BaseRepresentation
bin100110001101101100…
…101010111000011101
310220220120221201121120
4212031230222320131
51133013143044401
630503322121153
72651545162125
oct461554527035
9126816851546
1041032003101
1116446550271
127b516501b9
133b3bb1639b
141db3689c85
1511023da836
hex98db2ae1d

41032003101 has 4 divisors (see below), whose sum is σ = 54709337472. Its totient is φ = 27354668732.

The previous prime is 41032003091. The next prime is 41032003139. The reversal of 41032003101 is 10130023014.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41032003101 - 25 = 41032003069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41032003141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6838667181 + ... + 6838667186.

It is an arithmetic number, because the mean of its divisors is an integer number (13677334368).

Almost surely, 241032003101 is an apocalyptic number.

It is an amenable number.

41032003101 is a deficient number, since it is larger than the sum of its proper divisors (13677334371).

41032003101 is a wasteful number, since it uses less digits than its factorization.

41032003101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13677334370.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 41032003101 its reverse (10130023014), we get a palindrome (51162026115).

The spelling of 41032003101 in words is "forty-one billion, thirty-two million, three thousand, one hundred one".

Divisors: 1 3 13677334367 41032003101