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41041312181 is a prime number
BaseRepresentation
bin100110001110010000…
…001011100110110101
310220221020110200021022
4212032100023212311
51133023033442211
630504253430525
72652020253242
oct461620134665
9126836420238
1041041312181
1116450829321
127b5479b445
133b40a2560c
141db49d05c9
151103128bdb
hex98e40b9b5

41041312181 has 2 divisors, whose sum is σ = 41041312182. Its totient is φ = 41041312180.

The previous prime is 41041312177. The next prime is 41041312187. The reversal of 41041312181 is 18121314014.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27203554225 + 13837757956 = 164935^2 + 117634^2 .

It is a cyclic number.

It is not a de Polignac number, because 41041312181 - 22 = 41041312177 is a prime.

It is a super-2 number, since 2×410413121812 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 41041312181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41041312187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20520656090 + 20520656091.

It is an arithmetic number, because the mean of its divisors is an integer number (20520656091).

Almost surely, 241041312181 is an apocalyptic number.

It is an amenable number.

41041312181 is a deficient number, since it is larger than the sum of its proper divisors (1).

41041312181 is an equidigital number, since it uses as much as digits as its factorization.

41041312181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 41041312181 its reverse (18121314014), we get a palindrome (59162626195).

The spelling of 41041312181 in words is "forty-one billion, forty-one million, three hundred twelve thousand, one hundred eighty-one".