4104414131 has 4 divisors (see below), whose sum is σ = 4120384872. Its totient is φ = 4088443392.

The previous prime is 4104414011. The next prime is 4104414133. The reversal of 4104414131 is 1314144014.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1314144014 = 2 ⋅657072007.

It is a cyclic number.

It is not a de Polignac number, because 4104414131 - 2¹⁴ = 4104397747 is a prime.

It is a super-2 number, since 2×4104414131² = 33692430717504970322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4104414097 and 4104414106.

It is not an unprimeable number, because it can be changed into a prime (4104414133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7984985 + ... + 7985498.

It is an arithmetic number, because the mean of its divisors is an integer number (1030096218).

Almost surely, 2^4104414131 is an apocalyptic number.

4104414131 is a deficient number, since it is larger than the sum of its proper divisors (15970741).

4104414131 is a wasteful number, since it uses less digits than its factorization.

4104414131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15970740.

The product of its (nonzero) digits is 768, while the sum is 23.

The square root of 4104414131 is about 64065.7016741407. The cubic root of 4104414131 is about 1601.0948406306.

Adding to 4104414131 its reverse (1314144014), we get a palindrome (5418558145).

The spelling of 4104414131 in words is "four billion, one hundred four million, four hundred fourteen thousand, one hundred thirty-one".