41100214433 has 2 divisors, whose sum is σ = 41100214434. Its totient is φ = 41100214432.

The previous prime is 41100214381. The next prime is 41100214453. The reversal of 41100214433 is 33441200114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37091678464 + 4008535969 = 192592^2 + 63313^2 .

It is a cyclic number.

It is not a de Polignac number, because 41100214433 - 2¹² = 41100210337 is a prime.

It is a super-2 number, since 2×41100214433² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41100214399 and 41100214408.

It is not a weakly prime, because it can be changed into another prime (41100214453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20550107216 + 20550107217.

It is an arithmetic number, because the mean of its divisors is an integer number (20550107217).

Almost surely, 2^41100214433 is an apocalyptic number.

It is an amenable number.

41100214433 is a deficient number, since it is larger than the sum of its proper divisors (1).

41100214433 is an equidigital number, since it uses as much as digits as its factorization.

41100214433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 41100214433 its reverse (33441200114), we get a palindrome (74541414547).

The spelling of 41100214433 in words is "forty-one billion, one hundred million, two hundred fourteen thousand, four hundred thirty-three".