Base | Representation |
---|---|
bin | 100110010001110001… |
… | …101101011011101101 |
3 | 10221002100201022222012 |
4 | 212101301231123231 |
5 | 1133133202330013 |
6 | 30514204531005 |
7 | 2653335626444 |
oct | 462161553355 |
9 | 127070638865 |
10 | 41100433133 |
11 | 16481139811 |
12 | 7b70550a65 |
13 | 3b50055426 |
14 | 1dbc7bdd5b |
15 | 11084061a8 |
hex | 991c6d6ed |
41100433133 has 2 divisors, whose sum is σ = 41100433134. Its totient is φ = 41100433132.
The previous prime is 41100433123. The next prime is 41100433151. The reversal of 41100433133 is 33133400114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40805212009 + 295221124 = 202003^2 + 17182^2 .
It is a cyclic number.
It is not a de Polignac number, because 41100433133 - 212 = 41100429037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41100433099 and 41100433108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41100433123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20550216566 + 20550216567.
It is an arithmetic number, because the mean of its divisors is an integer number (20550216567).
Almost surely, 241100433133 is an apocalyptic number.
It is an amenable number.
41100433133 is a deficient number, since it is larger than the sum of its proper divisors (1).
41100433133 is an equidigital number, since it uses as much as digits as its factorization.
41100433133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 41100433133 its reverse (33133400114), we get a palindrome (74233833247).
The spelling of 41100433133 in words is "forty-one billion, one hundred million, four hundred thirty-three thousand, one hundred thirty-three".
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