Base | Representation |
---|---|
bin | 10010101100010011101010… |
… | …01101100100011011010011 |
3 | 12101112120200102122120120122 |
4 | 21112021311031210123103 |
5 | 20341430114144422232 |
6 | 223231141441500455 |
7 | 11441503231005326 |
oct | 1126116515443323 |
9 | 171476612576518 |
10 | 41104803514067 |
11 | 121084a3a902a7 |
12 | 473a47764172b |
13 | 19c22215a7947 |
14 | a216a98d87bd |
15 | 4b436c261312 |
hex | 2562753646d3 |
41104803514067 has 2 divisors, whose sum is σ = 41104803514068. Its totient is φ = 41104803514066.
The previous prime is 41104803514039. The next prime is 41104803514069. The reversal of 41104803514067 is 76041530840114.
41104803514067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41104803514067 - 212 = 41104803509971 is a prime.
Together with 41104803514069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (41104803514069) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20552401757033 + 20552401757034.
It is an arithmetic number, because the mean of its divisors is an integer number (20552401757034).
Almost surely, 241104803514067 is an apocalyptic number.
41104803514067 is a deficient number, since it is larger than the sum of its proper divisors (1).
41104803514067 is an equidigital number, since it uses as much as digits as its factorization.
41104803514067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 322560, while the sum is 44.
The spelling of 41104803514067 in words is "forty-one trillion, one hundred four billion, eight hundred three million, five hundred fourteen thousand, sixty-seven".
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