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41112053143 = 75873150449
BaseRepresentation
bin100110010010011110…
…000010010110010111
310221010011120200121221
4212102132002112113
51133144141200033
630515301551211
72653536454150
oct462236022627
9127104520557
1041112053143
1116487756027
127b74415507
133b52593485
141dc0166927
15110944e12d
hex992782597

41112053143 has 4 divisors (see below), whose sum is σ = 46985203600. Its totient is φ = 35238902688.

The previous prime is 41112053119. The next prime is 41112053183. The reversal of 41112053143 is 34135021114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41112053143 - 213 = 41112044951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41112053183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2936575218 + ... + 2936575231.

It is an arithmetic number, because the mean of its divisors is an integer number (11746300900).

Almost surely, 241112053143 is an apocalyptic number.

41112053143 is a deficient number, since it is larger than the sum of its proper divisors (5873150457).

41112053143 is an equidigital number, since it uses as much as digits as its factorization.

41112053143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5873150456.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41112053143 its reverse (34135021114), we get a palindrome (75247074257).

The spelling of 41112053143 in words is "forty-one billion, one hundred twelve million, fifty-three thousand, one hundred forty-three".

Divisors: 1 7 5873150449 41112053143