Base | Representation |
---|---|
bin | 1111010100001101… |
… | …1010110110100101 |
3 | 101121112011102000112 |
4 | 3311003122312211 |
5 | 31404444024331 |
6 | 1515543422405 |
7 | 203611411121 |
oct | 36503326645 |
9 | 11545142015 |
10 | 4111314341 |
11 | 181a803352 |
12 | 968a54a05 |
13 | 5069c70a4 |
14 | 2b004c581 |
15 | 190e1232b |
hex | f50dada5 |
4111314341 has 2 divisors, whose sum is σ = 4111314342. Its totient is φ = 4111314340.
The previous prime is 4111314313. The next prime is 4111314353. The reversal of 4111314341 is 1434131114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3881913025 + 229401316 = 62305^2 + 15146^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4111314341 is a prime.
It is a super-2 number, since 2×41113143412 = 33805811221024528562, which contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4111314941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055657170 + 2055657171.
It is an arithmetic number, because the mean of its divisors is an integer number (2055657171).
Almost surely, 24111314341 is an apocalyptic number.
It is an amenable number.
4111314341 is a deficient number, since it is larger than the sum of its proper divisors (1).
4111314341 is an equidigital number, since it uses as much as digits as its factorization.
4111314341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 23.
The square root of 4111314341 is about 64119.5316654762. The cubic root of 4111314341 is about 1601.9915748078.
Adding to 4111314341 its reverse (1434131114), we get a palindrome (5545445455).
The spelling of 4111314341 in words is "four billion, one hundred eleven million, three hundred fourteen thousand, three hundred forty-one".
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