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41114120335 = 58222824067
BaseRepresentation
bin100110010010100101…
…111011000010001111
310221010022110201021121
4212102211323002033
51133200203322320
630515414141411
72653563154021
oct462245730217
9127108421247
1041114120335
1116488938152
127b75051867
133b52b38372
141dc0544011
15110970b8aa
hex99297b08f

41114120335 has 4 divisors (see below), whose sum is σ = 49336944408. Its totient is φ = 32891296264.

The previous prime is 41114120293. The next prime is 41114120347. The reversal of 41114120335 is 53302141114.

41114120335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41114120335 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4111412029 + ... + 4111412038.

It is an arithmetic number, because the mean of its divisors is an integer number (12334236102).

Almost surely, 241114120335 is an apocalyptic number.

41114120335 is a deficient number, since it is larger than the sum of its proper divisors (8222824073).

41114120335 is an equidigital number, since it uses as much as digits as its factorization.

41114120335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8222824072.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41114120335 its reverse (53302141114), we get a palindrome (94416261449).

The spelling of 41114120335 in words is "forty-one billion, one hundred fourteen million, one hundred twenty thousand, three hundred thirty-five".

Divisors: 1 5 8222824067 41114120335