4111412131 has 2 divisors, whose sum is σ = 4111412132. Its totient is φ = 4111412130.

The previous prime is 4111412119. The next prime is 4111412143. The reversal of 4111412131 is 1312141114.

It is a balanced prime because it is at equal distance from previous prime (4111412119) and next prime (4111412143).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4111412131 is a prime.

It is a super-2 number, since 2×4111412131² = 33807419421867922322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4111412099 and 4111412108.

It is not a weakly prime, because it can be changed into another prime (4111412101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055706065 + 2055706066.

It is an arithmetic number, because the mean of its divisors is an integer number (2055706066).

Almost surely, 2^4111412131 is an apocalyptic number.

4111412131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111412131 is an equidigital number, since it uses as much as digits as its factorization.

4111412131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 19.

The square root of 4111412131 is about 64120.2942210966. The cubic root of 4111412131 is about 1602.0042761405.

Adding to 4111412131 its reverse (1312141114), we get a palindrome (5423553245).

The spelling of 4111412131 in words is "four billion, one hundred eleven million, four hundred twelve thousand, one hundred thirty-one".