4111412130 has 144 divisors (see below), whose sum is σ = 12520380600. Its totient is φ = 933295104.

The previous prime is 4111412119. The next prime is 4111412131. The reversal of 4111412130 is 312141114.

4111412130 is a `hidden beast` number, since 411 + 1 + 41 + 213 + 0 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 3655290681 + 456121449 = 60459^2 + 21357^2 .

It is a super-2 number, since 2×4111412130² = 33807419405422273800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (4111412131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 653962 + ... + 660218.

Almost surely, 2^4111412130 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 4111412130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6260190300).

4111412130 is an abundant number, since it is smaller than the sum of its proper divisors (8408968470).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4111412130 is a wasteful number, since it uses less digits than its factorization.

4111412130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6433 (or 6423 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

The square root of 4111412130 is about 64120.2942132988. The cubic root of 4111412130 is about 1602.0042760106.

Adding to 4111412130 its reverse (312141114), we get a palindrome (4423553244).

The spelling of 4111412130 in words is "four billion, one hundred eleven million, four hundred twelve thousand, one hundred thirty".