Base | Representation |
---|---|
bin | 100110010010100101… |
… | …111011011101111111 |
3 | 10221010022110210201101 |
4 | 212102211323131333 |
5 | 1133200203401421 |
6 | 30515414153531 |
7 | 2653563162136 |
oct | 462245733577 |
9 | 127108423641 |
10 | 41114122111 |
11 | 16488939517 |
12 | 7b750528a7 |
13 | 3b52b3910a |
14 | 1dc054491d |
15 | 110970c191 |
hex | 99297b77f |
41114122111 has 2 divisors, whose sum is σ = 41114122112. Its totient is φ = 41114122110.
The previous prime is 41114122087. The next prime is 41114122123. The reversal of 41114122111 is 11122141114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41114122111 - 213 = 41114113919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41114182111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20557061055 + 20557061056.
It is an arithmetic number, because the mean of its divisors is an integer number (20557061056).
Almost surely, 241114122111 is an apocalyptic number.
41114122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
41114122111 is an equidigital number, since it uses as much as digits as its factorization.
41114122111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 64, while the sum is 19.
Adding to 41114122111 its reverse (11122141114), we get a palindrome (52236263225).
The spelling of 41114122111 in words is "forty-one billion, one hundred fourteen million, one hundred twenty-two thousand, one hundred eleven".
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