Base | Representation |
---|---|
bin | 1011111101111011011… |
… | …00010110011111000101 |
3 | 1110022101112122112200012 |
4 | 11332331230112133011 |
5 | 23214121312212011 |
6 | 512523225400005 |
7 | 41465012562146 |
oct | 5767554263705 |
9 | 1408345575605 |
10 | 411204413381 |
11 | 149433197a73 |
12 | 6783b639005 |
13 | 2ca12a06a48 |
14 | 15c8c283acd |
15 | aa6a3b4a8b |
hex | 5fbdb167c5 |
411204413381 has 2 divisors, whose sum is σ = 411204413382. Its totient is φ = 411204413380.
The previous prime is 411204413357. The next prime is 411204413383. The reversal of 411204413381 is 183314402114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 262620376225 + 148584037156 = 512465^2 + 385466^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-411204413381 is a prime.
It is a super-2 number, since 2×4112044133812 (a number of 24 digits) contains 22 as substring.
Together with 411204413383, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411204413383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205602206690 + 205602206691.
It is an arithmetic number, because the mean of its divisors is an integer number (205602206691).
Almost surely, 2411204413381 is an apocalyptic number.
It is an amenable number.
411204413381 is a deficient number, since it is larger than the sum of its proper divisors (1).
411204413381 is an equidigital number, since it uses as much as digits as its factorization.
411204413381 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 32.
Adding to 411204413381 its reverse (183314402114), we get a palindrome (594518815495).
The spelling of 411204413381 in words is "four hundred eleven billion, two hundred four million, four hundred thirteen thousand, three hundred eighty-one".
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