Base | Representation |
---|---|
bin | 100110010011000001… |
… | …011110011101100101 |
3 | 10221010211001200101001 |
4 | 212103001132131211 |
5 | 1133204030441313 |
6 | 30520233033301 |
7 | 2654011436230 |
oct | 462301363545 |
9 | 127124050331 |
10 | 41121343333 |
11 | 16491a20974 |
12 | 7b77555831 |
13 | 3b54496c25 |
14 | 1dc14a4417 |
15 | 110a186add |
hex | 99305e765 |
41121343333 has 8 divisors (see below), whose sum is σ = 49760281152. Its totient is φ = 33173520576.
The previous prime is 41121343301. The next prime is 41121343337. The reversal of 41121343333 is 33334312114.
41121343333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 41121343333 - 25 = 41121343301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41121343337) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 172778635 + ... + 172778872.
It is an arithmetic number, because the mean of its divisors is an integer number (6220035144).
Almost surely, 241121343333 is an apocalyptic number.
It is an amenable number.
41121343333 is a deficient number, since it is larger than the sum of its proper divisors (8638937819).
41121343333 is a wasteful number, since it uses less digits than its factorization.
41121343333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 345557531.
The product of its digits is 7776, while the sum is 28.
Adding to 41121343333 its reverse (33334312114), we get a palindrome (74455655447).
The spelling of 41121343333 in words is "forty-one billion, one hundred twenty-one million, three hundred forty-three thousand, three hundred thirty-three".
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