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4112212103 is a prime number
BaseRepresentation
bin1111010100011011…
…0110000010000111
3101121120212000111222
43311012312002013
531410211241403
61520014550555
7203622140366
oct36506660207
911546760458
104112212103
1118202668aa
1296920845b
13506c4c8cc
142b02037dd
1519103d338
hexf51b6087

4112212103 has 2 divisors, whose sum is σ = 4112212104. Its totient is φ = 4112212102.

The previous prime is 4112212063. The next prime is 4112212141. The reversal of 4112212103 is 3012122114.

4112212103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4112212103 - 28 = 4112211847 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4112212303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056106051 + 2056106052.

It is an arithmetic number, because the mean of its divisors is an integer number (2056106052).

Almost surely, 24112212103 is an apocalyptic number.

4112212103 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112212103 is an equidigital number, since it uses as much as digits as its factorization.

4112212103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 4112212103 is about 64126.5319739030. The cubic root of 4112212103 is about 1602.1081719484.

Adding to 4112212103 its reverse (3012122114), we get a palindrome (7124334217).

The spelling of 4112212103 in words is "four billion, one hundred twelve million, two hundred twelve thousand, one hundred three".