Base | Representation |
---|---|
bin | 10010101100110100010001… |
… | …11100111000101111101111 |
3 | 12101121020212210202120222012 |
4 | 21112122020330320233233 |
5 | 20342222000011214401 |
6 | 223243155220111435 |
7 | 11442663201255032 |
oct | 1126321074705757 |
9 | 171536783676865 |
10 | 41122314554351 |
11 | 1211496a567018 |
12 | 4741943b3557b |
13 | 19c3a8241a344 |
14 | a2248b405019 |
15 | 4b4a447328bb |
hex | 256688f38bef |
41122314554351 has 4 divisors (see below), whose sum is σ = 41529466183704. Its totient is φ = 40715162925000.
The previous prime is 41122314554317. The next prime is 41122314554353. The reversal of 41122314554351 is 15345541322114.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 41122314554351 - 230 = 41121240812527 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 41122314554299 and 41122314554308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41122314554353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203575814525 + ... + 203575814726.
It is an arithmetic number, because the mean of its divisors is an integer number (10382366545926).
Almost surely, 241122314554351 is an apocalyptic number.
41122314554351 is a deficient number, since it is larger than the sum of its proper divisors (407151629353).
41122314554351 is a wasteful number, since it uses less digits than its factorization.
41122314554351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407151629352.
The product of its digits is 288000, while the sum is 41.
Adding to 41122314554351 its reverse (15345541322114), we get a palindrome (56467855876465).
The spelling of 41122314554351 in words is "forty-one trillion, one hundred twenty-two billion, three hundred fourteen million, five hundred fifty-four thousand, three hundred fifty-one".
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