Base | Representation |
---|---|
bin | 10010101100110101100100… |
… | …11011000100010111001111 |
3 | 12101121022200021222202121212 |
4 | 21112122302123010113033 |
5 | 20342224411121111421 |
6 | 223243352233045035 |
7 | 11443016350262441 |
oct | 1126326233042717 |
9 | 171538607882555 |
10 | 41123010332111 |
11 | 12115197292164 |
12 | 4741ab8b5677b |
13 | 19c3b6360b966 |
14 | a225159a0491 |
15 | 4b4a8586de5b |
hex | 2566b26c45cf |
41123010332111 has 2 divisors, whose sum is σ = 41123010332112. Its totient is φ = 41123010332110.
The previous prime is 41123010332101. The next prime is 41123010332137. The reversal of 41123010332111 is 11123301032114.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41123010332111 is a prime.
It is a super-3 number, since 3×411230103321113 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41123010332101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20561505166055 + 20561505166056.
It is an arithmetic number, because the mean of its divisors is an integer number (20561505166056).
Almost surely, 241123010332111 is an apocalyptic number.
41123010332111 is a deficient number, since it is larger than the sum of its proper divisors (1).
41123010332111 is an equidigital number, since it uses as much as digits as its factorization.
41123010332111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 41123010332111 its reverse (11123301032114), we get a palindrome (52246311364225).
The spelling of 41123010332111 in words is "forty-one trillion, one hundred twenty-three billion, ten million, three hundred thirty-two thousand, one hundred eleven".
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