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4112304131030 = 251732377054411
BaseRepresentation
bin111011110101111000011…
…011010100101111010110
3112120010120112201122212112
4323311320123110233112
51014333444324143110
612425055541151022
7603050505241544
oct73657033245726
915503515648775
104112304131030
1113460225244a7
12564baa3bb472
1323aa33785b84
14103072548d94
1571e854dd405
hex3bd786d4bd6

4112304131030 has 16 divisors (see below), whose sum is σ = 7444934418384. Its totient is φ = 1635413434080.

The previous prime is 4112304131029. The next prime is 4112304131059. The reversal of 4112304131030 is 301314032114.

It is a super-2 number, since 2×41123041310302 (a number of 26 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4112304130987 and 4112304131005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1188525476 + ... + 1188528935.

It is an arithmetic number, because the mean of its divisors is an integer number (465308401149).

Almost surely, 24112304131030 is an apocalyptic number.

4112304131030 is a deficient number, since it is larger than the sum of its proper divisors (3332630287354).

4112304131030 is a wasteful number, since it uses less digits than its factorization.

4112304131030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2377054591.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 4112304131030 its reverse (301314032114), we get a palindrome (4413618163144).

The spelling of 4112304131030 in words is "four trillion, one hundred twelve billion, three hundred four million, one hundred thirty-one thousand, thirty".

Divisors: 1 2 5 10 173 346 865 1730 2377054411 4754108822 11885272055 23770544110 411230413103 822460826206 2056152065515 4112304131030