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41123242241231 is a prime number
BaseRepresentation
bin10010101100110110000000…
…01111101110110011001111
312101121100021110100222010112
421112123000033232303033
520342230400003204411
6223243431235430235
711443025164416353
oct1126330017566317
9171540243328115
1041123242241231
11121152a6189997
124741b6275537b
1319c3b9c688ba7
14a225386cb463
154b4a9adccb8b
hex2566c03eeccf

41123242241231 has 2 divisors, whose sum is σ = 41123242241232. Its totient is φ = 41123242241230.

The previous prime is 41123242241189. The next prime is 41123242241233. The reversal of 41123242241231 is 13214224232114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41123242241231 - 214 = 41123242224847 is a prime.

It is a super-2 number, since 2×411232422412312 (a number of 28 digits) contains 22 as substring.

Together with 41123242241233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41123242241233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20561621120615 + 20561621120616.

It is an arithmetic number, because the mean of its divisors is an integer number (20561621120616).

Almost surely, 241123242241231 is an apocalyptic number.

41123242241231 is a deficient number, since it is larger than the sum of its proper divisors (1).

41123242241231 is an equidigital number, since it uses as much as digits as its factorization.

41123242241231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18432, while the sum is 32.

Adding to 41123242241231 its reverse (13214224232114), we get a palindrome (54337466473345).

The spelling of 41123242241231 in words is "forty-one trillion, one hundred twenty-three billion, two hundred forty-two million, two hundred forty-one thousand, two hundred thirty-one".