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4112404022413 is a prime number
BaseRepresentation
bin111011110101111110011…
…000011000010010001101
3112120010211111200200002101
4323311332120120102031
51014334200412204123
612425113510155101
7603053130302221
oct73657630302215
915503744620071
104112404022413
111346073951365
12565017952a91
1323aa4b38c0bb
1410308190c781
1571e8e170aad
hex3bd7e61848d

4112404022413 has 2 divisors, whose sum is σ = 4112404022414. Its totient is φ = 4112404022412.

The previous prime is 4112404022399. The next prime is 4112404022417. The reversal of 4112404022413 is 3142204042114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4044334168809 + 68069853604 = 2011053^2 + 260902^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112404022413 - 229 = 4111867151501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4112404022417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056202011206 + 2056202011207.

It is an arithmetic number, because the mean of its divisors is an integer number (2056202011207).

Almost surely, 24112404022413 is an apocalyptic number.

It is an amenable number.

4112404022413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112404022413 is an equidigital number, since it uses as much as digits as its factorization.

4112404022413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 4112404022413 its reverse (3142204042114), we get a palindrome (7254608064527).

The spelling of 4112404022413 in words is "four trillion, one hundred twelve billion, four hundred four million, twenty-two thousand, four hundred thirteen".