411241000320 has 512 divisors, whose sum is σ = 1512793497600. Its totient is φ = 105468272640.

The previous prime is 411241000271. The next prime is 411241000337. The reversal of 411241000320 is 23000142114.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 411241000293 and 411241000302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 89456262 + ... + 89460858.

It is an arithmetic number, because the mean of its divisors is an integer number (2954674800).

Almost surely, 2^411241000320 is an apocalyptic number.

411241000320 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 411241000320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (756396748800).

411241000320 is an abundant number, since it is smaller than the sum of its proper divisors (1101552497280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

411241000320 is a wasteful number, since it uses less digits than its factorization.

With its predecessor (411241000319) it forms an eRAP, since the sums of their prime factors are consecutive (4822 and 4823).

411241000320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4823 (or 4805 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 411241000320 its reverse (23000142114), we get a palindrome (434241142434).

The spelling of 411241000320 in words is "four hundred eleven billion, two hundred forty-one million, three hundred twenty", and thus it is an aban number.