411242153021309 has 2 divisors, whose sum is σ = 411242153021310. Its totient is φ = 411242153021308.

The previous prime is 411242153021267. The next prime is 411242153021311. The reversal of 411242153021309 is 903120351242114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 405268635751225 + 5973517270084 = 20131285^2 + 2444078^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-411242153021309 is a prime.

Together with 411242153021311, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411242153321309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205621076510654 + 205621076510655.

It is an arithmetic number, because the mean of its divisors is an integer number (205621076510655).

Almost surely, 2^{411242153021309} is an apocalyptic number.

It is an amenable number.

411242153021309 is a deficient number, since it is larger than the sum of its proper divisors (1).

411242153021309 is an equidigital number, since it uses as much as digits as its factorization.

411242153021309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 411242153021309 in words is "four hundred eleven trillion, two hundred forty-two billion, one hundred fifty-three million, twenty-one thousand, three hundred nine".