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4112440431000 = 2335311211329037
BaseRepresentation
bin111011110110000000100…
…011010001000110011000
3112120010221001012102021120
4323312000203101012120
51014334234222243000
612425121250405240
7603054051621546
oct73660043210630
915503831172246
104112440431000
111346092459700
12565027b90820
1323aa55a99045
141030866a8d96
1571e924636a0
hex3bd808d1198

4112440431000 has 192 divisors, whose sum is σ = 14103292825440. Its totient is φ = 996955168000.

The previous prime is 4112440430963. The next prime is 4112440431017. The reversal of 4112440431000 is 1340442114.

It is a super-2 number, since 2×41124404310002 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5301519 + ... + 6027518.

Almost surely, 24112440431000 is an apocalyptic number.

4112440431000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

4112440431000 is an abundant number, since it is smaller than the sum of its proper divisors (9990852394440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4112440431000 is a wasteful number, since it uses less digits than its factorization.

4112440431000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11329083 (or 11329058 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 4112440431000 its reverse (1340442114), we get a palindrome (4113780873114).

The spelling of 4112440431000 in words is "four trillion, one hundred twelve billion, four hundred forty million, four hundred thirty-one thousand".