41125000843 has 2 divisors, whose sum is σ = 41125000844. Its totient is φ = 41125000842.

The previous prime is 41125000811. The next prime is 41125000871. The reversal of 41125000843 is 34800052114.

It is an a-pointer prime, because the next prime (41125000871) can be obtained adding 41125000843 to its sum of digits (28).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41125000843 - 2⁵ = 41125000811 is a prime.

It is not a weakly prime, because it can be changed into another prime (41125009843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20562500421 + 20562500422.

It is an arithmetic number, because the mean of its divisors is an integer number (20562500422).

Almost surely, 2^41125000843 is an apocalyptic number.

41125000843 is a deficient number, since it is larger than the sum of its proper divisors (1).

41125000843 is an equidigital number, since it uses as much as digits as its factorization.

41125000843 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 41125000843 its reverse (34800052114), we get a palindrome (75925052957).

The spelling of 41125000843 in words is "forty-one billion, one hundred twenty-five million, eight hundred forty-three", and thus it is an aban number.