Base | Representation |
---|---|
bin | 100110010011001111… |
… | …011011011010100111 |
3 | 10221011001221111120102 |
4 | 212103033123122213 |
5 | 1133211000011441 |
6 | 30520443254315 |
7 | 2654054511503 |
oct | 462317333247 |
9 | 127131844512 |
10 | 41125000871 |
11 | 16493a99929 |
12 | 7b7881a39b |
13 | 3b55177956 |
14 | 1dc1b77303 |
15 | 110a65a69b |
hex | 9933db6a7 |
41125000871 has 2 divisors, whose sum is σ = 41125000872. Its totient is φ = 41125000870.
The previous prime is 41125000843. The next prime is 41125000879. The reversal of 41125000871 is 17800052114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41125000871 - 222 = 41120806567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41125000879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20562500435 + 20562500436.
It is an arithmetic number, because the mean of its divisors is an integer number (20562500436).
Almost surely, 241125000871 is an apocalyptic number.
41125000871 is a deficient number, since it is larger than the sum of its proper divisors (1).
41125000871 is an equidigital number, since it uses as much as digits as its factorization.
41125000871 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2240, while the sum is 29.
Adding to 41125000871 its reverse (17800052114), we get a palindrome (58925052985).
The spelling of 41125000871 in words is "forty-one billion, one hundred twenty-five million, eight hundred seventy-one", and thus it is an aban number.
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